Swindler's Dice
Braingle.com
on
Published in Brain Teasers
As you have guessed...the bet is not fair. He had calculated the probability wrongly. Probability does not accumulate, like 1/6 x 3.
The probability of the man not getting a ONE in three throws is: 5/6 x 5/6 x 5/6, which is 125/216. This is the probability of the swindler winning.
Hence, the remaining fraction, 91/216, is the actual chances of the man winning.
Today's brain teaser courtesy of Braingle.com.